that syntax is wrong; Fortran generally doesn't use
 two equal signs "==" for that purpose.

prost,
if I put a number is working:

parameter=5

Read(1,*)a
If (a==(5))
read(1,*)b
write(2,*)b
end if


but not if I put:
If (a==(parameter))

By default both parameter and a are real floating point numbers. It is considered bad fortran practice to compare two real numbers for equality, since you are relying too much on the precision of the hardware and software. Variable a may be stored as 5.0000001 and parameter may be stored as 4.99999999


Also 5 on its own is considered to be an integer, you should use 5.0 for single precision or 5.0D0 for double precision.

And in the dear dead days beyond recall "==" was .EQ.

I still use .EQ.  !

johnhors,

It still doesn't work even If I define parameter and a as integer or as real.

If I use:

If (a==(parameter))

it says "user breakpoint called from code 0x7c901230".

what level of Fortran did they introduce "=="? I too still use .EQ.

Try using something else other than parameter.  parameter is a keyword; not a reserved word: just a keyword.  It is recognized as part of the syntax and you are allowed to use it but it can be confusing and some compilers may not like it.

In Fortran, if you don't declare a variable, and it begins with letters a-h, o-z, it is real.  Real, real comparisons don't always work.

Thanks to everybody now is working!

The relief is palpable...

.EQ. rules ok...

ehehehe thanks again

I think you all will find that "=="  is nowadays much more commonly used than ".EQ.".   I'd venture that this has been true for more than 10 years now for those working with Fortran90 or beyond.

Also...  the above code now works due to the use of the variable PARAM.  The symbol used to check for equality is irrelevant.

Dan    
dan@dtware.com

Never.

The sky is falling...

"==" in FORTRAN.

Doomed, I tell ye, doomed.