fluid mechanics
fluid mechanics
(OP)
simple question.
How do I calculate the velocity of water leaving a tap of characteristic length 0.001m. I know the static and atmospheric pressures. I also know density and height. I guess I have to use
velocity x density x characteristic length divided by viscosity
I know this equals the reynolds number and was hoping I could rearrange the formula but don't have the viscosity or Re.
Can I do it another way?
How do I calculate the velocity of water leaving a tap of characteristic length 0.001m. I know the static and atmospheric pressures. I also know density and height. I guess I have to use
velocity x density x characteristic length divided by viscosity
I know this equals the reynolds number and was hoping I could rearrange the formula but don't have the viscosity or Re.
Can I do it another way?
RE: fluid mechanics
Best Regards
Morten
RE: fluid mechanics
you collect fixed amount of water eg 10 lit. you note down time required to get 1000 lit. Say time required = 20 second
so flow rate = 1000 lit = 1 m3 / 10sec = 0.1 m3 /s .now you divide the flow rate by flow area , you will get velocity of water.
Pawan kumar (chemical engineer)
RE: fluid mechanics