psmi8905
Mechanical
- May 9, 2014
- 4
All,
I'm a mechanical engineer at a steel mill and today I was asked to design a rack which will hold steel coils (see the attached picture). The coil rack shown in the picture is in use at a sister mill whose coils weigh only 50,000 lbs, whereas our coils weigh up to 90,000 lbs. As you can see, the beams are resting on the ground. I'm at a loss as to how to calculate the required beam size to support these coils. The only stipulation is that the overall height of the beam has to be 14", so it'll need to be a W 14 X (???). Another issue is that our coil outer diameters range from 56" all the way up to 77". Of course, a 56" O.D. coil will not weigh 90 kip, but they are substantially heavy as well (around 48,000 lbs). I think it would be most practical to forego web stiffeners and just weld a plate to the outside of the flanges on both sides of the beam; basically box in the I-beam. With that being said, do you guys have any advice for calculating the required beam section? Keep in mind that the weight of the coil will be shared over two I-beams, just as the attached picture shows.
-PS
I'm a mechanical engineer at a steel mill and today I was asked to design a rack which will hold steel coils (see the attached picture). The coil rack shown in the picture is in use at a sister mill whose coils weigh only 50,000 lbs, whereas our coils weigh up to 90,000 lbs. As you can see, the beams are resting on the ground. I'm at a loss as to how to calculate the required beam size to support these coils. The only stipulation is that the overall height of the beam has to be 14", so it'll need to be a W 14 X (???). Another issue is that our coil outer diameters range from 56" all the way up to 77". Of course, a 56" O.D. coil will not weigh 90 kip, but they are substantially heavy as well (around 48,000 lbs). I think it would be most practical to forego web stiffeners and just weld a plate to the outside of the flanges on both sides of the beam; basically box in the I-beam. With that being said, do you guys have any advice for calculating the required beam section? Keep in mind that the weight of the coil will be shared over two I-beams, just as the attached picture shows.
-PS