JRW261
All other factors being equal, as the water evaporates, it will form smaller drops, but I expect no more drops, therefore the surface area of the drops will decrease in absolute terms, but will increase in relative to mass of water terms. The outside factor will be shear on the drops due to motion in the inlet tract and compression and early parts of the power stroke. Also, water will collect on the walls and floor, making very large drops or puddles, so who knows the net result.
The cooling increases the density of the air, not the volume. The volume is virtually constant as it is defined by the dimension of the manifold, which only changes a few thou due to temperature changes of the metal. As you have higher density and similar volume, you have greater mass.
Water has a significantly lower evaporation rate than petrol, therefore, I would expect most of the evaporation to take place as the heat rises during the early stages of combustion, with very little occurring before the inlet valve closes.
The volume of liquid fuel and water vs volume of air is insignificant re volumetric efficiency, unless you are using nitro methane in high proportions.
JayMaechtlen
I agree pretty well with what you say, and any water vapour in the inlet tract will displace oxygen, but I feel there is very little volume in the liquid form, and only a small amount of evaporation before the inlet valve closes, then it cannot displace any oxygen.
Regards
pat
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