veritas
Electrical
- Oct 30, 2003
- 467
Hi
Could someone please explain the following from a VT spec.
Voltage ratio = (11kV/1.732):110V/1.732 : 110/3
There are two secondary windings. I understand that the primary has 11kV line-to-line volts and the 1st secondary winding has 110V line to line and 63.5V line to neutral. What puzzles me is why the 2nd winding (a broken delta one) is given as 110/3? does this mean the line to neutral volts = 36.67V?
I understand that the voltage at the broken delta would be 3V0 but am really puzzled by the 110/3.![[ponder] [ponder] [ponder]](/data/assets/smilies/ponder.gif)
Thanks.
Could someone please explain the following from a VT spec.
Voltage ratio = (11kV/1.732):110V/1.732 : 110/3
There are two secondary windings. I understand that the primary has 11kV line-to-line volts and the 1st secondary winding has 110V line to line and 63.5V line to neutral. What puzzles me is why the 2nd winding (a broken delta one) is given as 110/3? does this mean the line to neutral volts = 36.67V?
I understand that the voltage at the broken delta would be 3V0 but am really puzzled by the 110/3.
![[ponder] [ponder] [ponder]](/data/assets/smilies/ponder.gif)
Thanks.