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Volume of Oxygen 1
- Thread starter jaykay
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Your question looks like a thermodynamics question. I would try using the energy equation not at steady state to find the mass flow rate with respect to time. Then if you know the precentage of oxygen in what is being released then just find the volume of the total and multiply it by the percentage. That is the best idea I can come up with from what little information you provided.
The perfect gas law is PV=nRT: P-pressure in atmospheres, V-volume in liters, n-number of moles, R-gas constant (0.0821 liter-atmosphere/deg K/mole), /T temperature in deg K.
Of course you didn't specify the length of the hose, which makes a difference based on: V=sqrt(25000DP/L): V-air velocity in ft/sec, D- pipe diameyer in inches, P- pressure loss due to friction in oz/sq inch/ft, L-length in feet.
Then using CFM=60VA: CFM-cubic feet/minute, V-Velocity in ft/sec, A-cross sectional area of pipe.
The rest is just algebra.
Of course you didn't specify the length of the hose, which makes a difference based on: V=sqrt(25000DP/L): V-air velocity in ft/sec, D- pipe diameyer in inches, P- pressure loss due to friction in oz/sq inch/ft, L-length in feet.
Then using CFM=60VA: CFM-cubic feet/minute, V-Velocity in ft/sec, A-cross sectional area of pipe.
The rest is just algebra.
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