jfpe
Electrical
- Jul 18, 2007
- 104
I have a question regarding voltage drop calculations. I'm sure it's painfully simple, but it's been troubling me for a little while.
The electric services where I work are predominantly 120/208VAC 3-phase. Apartments and single family homes get 120/208VAC "single phase" or network service, which is two hots and a neutral from the 3-phase distribution system.
When I need to do 3-phase voltage drop calculation, I turn to Chapter 9, Table 9 in the NEC and calculate voltage drop as
VD (line-neutral) =R x Circuit Length x I
To calculate line to line voltage drop, I multiply by 1.73, so VD = 1.73 x R x L x I
When I need to calculate voltage drop in 120/208VAC "single phase" circuit, i.e. two hots and a neutral or commonly two hots and no neutral I want to follow the explanatory text following 215.2(A) in the NEC Handbook. and calculate voltage drop as VD = 2 x L x R x I.
What is the right way to calculate line to line voltage drop for 208VAC? Do I need a factor of 1.73 or 2?
Thanks,
John
The electric services where I work are predominantly 120/208VAC 3-phase. Apartments and single family homes get 120/208VAC "single phase" or network service, which is two hots and a neutral from the 3-phase distribution system.
When I need to do 3-phase voltage drop calculation, I turn to Chapter 9, Table 9 in the NEC and calculate voltage drop as
VD (line-neutral) =R x Circuit Length x I
To calculate line to line voltage drop, I multiply by 1.73, so VD = 1.73 x R x L x I
When I need to calculate voltage drop in 120/208VAC "single phase" circuit, i.e. two hots and a neutral or commonly two hots and no neutral I want to follow the explanatory text following 215.2(A) in the NEC Handbook. and calculate voltage drop as VD = 2 x L x R x I.
What is the right way to calculate line to line voltage drop for 208VAC? Do I need a factor of 1.73 or 2?
Thanks,
John