aroundhere
Petroleum
- Sep 21, 2006
- 175
I always like to test everything if possible. I have a design where I want a pin to shear once a given amount of torque is applied to the shaft. I want the .125 pin to shear when the torque is 120in-lb. I will have to find the correct material to use for the pin because I had to pick a size for the pin before I really knew what the torque would be. I thought the best way to test this would be to buy a beam type torque wrench and try to load it up while keeping an eye on the needle to see what the pin shears at. The 2 parts do have flats for wrenches. Let me know if there is a better way to do this without spending too much $. I found a beam type torque wrench on at mcmaster for $80 that is 0-600in-lb.
Since the pin size and the torque are set, the material of the dowel pin is what I have to determine. I can find a double shear number for 416 SS, but nothing for 316SS or 18-8SS. I would rather go with an off the shelf pin, but if im lucky enough to find a SS pin with the correct properties, im not sure how much the numbers can fluctuate between pins of the same material from different manfs or even the same manfs. This was the reason for the testing. Looks like I need a shear strength of 39,000psi. I typed this out below so I could document it and I figured someone would let me know if my numbers are off.Thanks for any input. I also have a sketch of the 2 parts with the pin installed. The pin has a slight press fit to keep it in place.
120in-lbs/.25R = 480lbs <--pin needs to shear at this force
.125^2 *.7854=.0123sq-in <--.125dia pin area
480lbs/.0123sq-in = 39,000 psi
Since the pin size and the torque are set, the material of the dowel pin is what I have to determine. I can find a double shear number for 416 SS, but nothing for 316SS or 18-8SS. I would rather go with an off the shelf pin, but if im lucky enough to find a SS pin with the correct properties, im not sure how much the numbers can fluctuate between pins of the same material from different manfs or even the same manfs. This was the reason for the testing. Looks like I need a shear strength of 39,000psi. I typed this out below so I could document it and I figured someone would let me know if my numbers are off.Thanks for any input. I also have a sketch of the 2 parts with the pin installed. The pin has a slight press fit to keep it in place.
120in-lbs/.25R = 480lbs <--pin needs to shear at this force
.125^2 *.7854=.0123sq-in <--.125dia pin area
480lbs/.0123sq-in = 39,000 psi