111R
Electrical
- May 4, 2012
- 114
Are there any IEEE standards or other technical papers that describe various methods used to store power transformers?
I've heard that it's a good idea to leave the cabinet heaters on for condensation control.
I've also heard of circulating current through the windings to keep moisture down in the paper and oil. With a 138kV/12.5kV, 20 MVA transformer with ~10% impedance, I'm not sure if it would be possible to get optimal current flow. 208V/3Ø is available, but connected to the low side with high side shorted will be too much current. Connected to the high side, the current will likely be too low to have any effect.
I'm assuming that 1/10th of the voltage on a transformer winding with 10% impedance will cause 100% of load current to flow. So, on the low side, 1250V will cause full load current to flow with the high side shorted. 208V will cause 1/6th of full load current to flow which will be ~150A...way above what is practical or possible. Connecting to the high side will reduce this by a factor of the turns ratio squared, so that will be probably be too low. Please let me know if I'm off on my math or understanding of how this works.
Thanks!
I've heard that it's a good idea to leave the cabinet heaters on for condensation control.
I've also heard of circulating current through the windings to keep moisture down in the paper and oil. With a 138kV/12.5kV, 20 MVA transformer with ~10% impedance, I'm not sure if it would be possible to get optimal current flow. 208V/3Ø is available, but connected to the low side with high side shorted will be too much current. Connected to the high side, the current will likely be too low to have any effect.
I'm assuming that 1/10th of the voltage on a transformer winding with 10% impedance will cause 100% of load current to flow. So, on the low side, 1250V will cause full load current to flow with the high side shorted. 208V will cause 1/6th of full load current to flow which will be ~150A...way above what is practical or possible. Connecting to the high side will reduce this by a factor of the turns ratio squared, so that will be probably be too low. Please let me know if I'm off on my math or understanding of how this works.
Thanks!