Steinmetz equation for loss

[jt83]

Can someone please show the Steinmetz equation presented in "classroom form" whereby the units cancel out and yield watts/m^3. The reference we found shows: Wh = n x f x B,
n = hysteresis coeff (J/m^3/cycle), f is Hz, B is in Weber/m^2.

I have seen B in terms of Tesla-m^2, but I understand Tesla to be Newton/A-m?

 

[7anoter4]

You are right. But, at first, for the record: the Steinmetz formulae it is as follows:
Wh = n x f x B^1.6 [joule/m^3/cycle] [n has to be in other units]
Or better:
Ph=h*f*Vol*(Bmax)^1.6 [w]
According to Maxwell law E=d(B*S)/dt [ limit (E)=limit(B*S/t ) when t tends to 0].
In MKSA units [IS]: E[Volt]; B[Wb/m^2=Tesla];S[m^2];t[sec] then from above Maxwell law we can write:
Volt=(Wb/m^2)*(m^2)/sec then: Volt=Wb/sec.
Since Nm=joule joule=watt*sec watt*sec=A*V*sec Volt=Wb/sec N*m=A*Wb Wb=N*m/A.
As Tesla=Wb/m^2 then Tesla=N/A/m.