Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations waross on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Steel wear factor

Status
Not open for further replies.

JeanMicheling

Mechanical
Oct 5, 2005
91
Hello folks,

I'm looking for a specific value regarding any kind of steel but Hardox 400 would be the best. So, I talked to the hardox people. Here is what I asked :




Here are the information on my application :



-It’s the same principle as a plain bearing. It’s a rotating pin with boundary-lubrication. A circular hardox 400 plate oscillates against another circular hardox 400 plate. The equation for calculating the absolute wear life is : t = pi*L*D*w/4*f1*f2*K*V*F where



t : life in hours

L: length

D : Diameter

w : wear

f1 : Motion-related factor

f2 : Environmental factor

K : Wear factor in/((psi)(ft/min)h)

V : linear speed

F : load



I’d like to know the wear factor K for the Hardox 400.


________________________


This formula comes from ''Mechanical Engineering Design'' by Shigley and Mischke. They provide some values for the Oiles, Polyactal, 66 Nylon, Phenol,...etc, but nothing in relation with steel. The only thing Hardox have about the wear is the Relative Wear Method. By comparing the material hardness, they can forecast what will be the hardox plate wear relative to other steels. Thus, assuming I can find the K factor for any kind of steel, a good approx. could be done. Does someone have any value for a well known steel (hardox 400 or scandia 400 if possible)? I can't believe I'm the first person in the world who want to know how long a homemade plane bearing with steel will last! According to Hardox, it seems to be.

Any help will be appreciate.

Thanks,
 
Replies continue below

Recommended for you

It is quite refreshing to learn that the wear factor K is believed to solve a problem. If you are dealing with research it may well be correct.
However in the real world it seems that many elements difficult to think of and impossible to quantify may be more important than an elegant formula.
If you have a problem with a specific application it may pay to perform some experiments where hardness would be only one of the important factors.
Surface finish, lubrication, cooling, removal of abraded particles, actual load, speed and mating material may play a conclusive part not reflected in the numerical value of K.

 
Goahead, you're right, I dream of a world where formulas would be as good as practice. But the problem is that this is the only way I have to get an idea of how long my system will last. I think I'll try to make a short scaling test and extrapolate the results. This is maybe the best way I'll get something close. If someone has a better idea, please let me know!
 
Steel against steel wear is only as good as the lubrication and cooling. My experience so far is to use 6,000 psi film strength on non distorting surfaces. If the mating surfaces distort under load there will be point pressure. This will cause heating, then galling of the surfaces. If there is adequate lubrication and stiffness A36 plates work fine together.
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor