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Steam Loss in Orifices

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omerada

Nuclear
Joined
Nov 3, 2006
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6
Location
US
People please help, I have been usuing this formula to calculate steam loss in orifices for years:

Q = 24.24 x Pa x d^2, Q = lbs/hr, Pa = Steam pressure, psia, and d = orifice diameter in inches. My boss wants to know where the constant 24.24 came from. I understand this is a variation of Navier's formula, I tried every formulation of Navier's formula and none gave me the constant 24.24, Does anybody know something that I missed?

Please help.
 
I think you have a typo. Napiers formula.

Regards
 
24.24=C*(pi/4)*sqrt(gc/(R*T)*k*(2/(k+1))^((k+1)/(k-1)))

C ranges from 0.6 to 1. It should be noted that this is for sonic flow, i.e., P2 < P1*(2/(k+1))^(k/(k-1))
 
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