Hello nhee
The start current is dependent on the motor characteristics and the load characterisitics. There are considerable differences between motors so it is difficult to apply rules for starting characteristics.
The start time is dependent on the inertia of the load and the acceleration torque applied to the load.
The acceleration torque is the difference between the "load torque" and the motor torque at all speeds.
If you can get the speed torque curve of the load, and the speed torque curve and speed current curve of the motor, you can calculate the start torque curves for the motor at different start currents and superimpose them on the load torque curve. The motor will only start if the motor torque (at the reduced start current) is higher than the load torque for all speeds from zero to full speed.
In the case of the fan, you will have an initial breakaway torque of perhaps 30%. The torque will then drop low and increase with the square of the speed.
It is common with reduced voltage starting for the torque to run out at around 70% speed unless the start current is increased, but it is very dependent on the motor and load characteristics.
If you download the Electrical calculations software from
you can load in your motor curves and load curves and see the effects of different types of starters and start currents on the start characterisics. If you know the load inertia, you can also get an indication of the start time.
From my experience, it is not uncommon for a fan to take in excess of 30 seconds to start due to the inertia of the fan.
With modern high efficiency motors, a start current of 400% commonly develops a relatively low start torque and high start torque machines often need a much higher start current in order to develop sufficient torque.
Best regards,
Mark Empson