Draw the FBD of inclined surface and write the equations of equilibrium ,
- μ is the friction btw the contact surfaces ,
- N is the vertical component to the inclined surface of P
Sum of the forces on X axis ;
Σ F x =0 = Fi- μN*Cos (α)- N*Sin (α) >>
Sum of the forces on Y axis ;
Σ F y =0 = N*Cos (α)- μN*Sin (α) -P
Combine these two equations and get the force F
Fi= P ( μ*Cos (α) + Sin (α) )/ ( Cos (α)- μ*Sin (α))
Then divide nominator and denominator to Cos (α)
Fi= P ( μ +TAN (α) )/ ( 1 - μ* TAN (α))
I could not find the mistake but this should be the way to derive.
P.S . = I assumed the driving force is Fi.
EDIT:Today Morning ,When i was preparing my post there were only OP 's post and SWComposites' post and my respond was the second.Later i looked to the Thread and see that my post is the 4th respond. If somebody out there can explain what could be the reason ?