shaft power

[lsm77]

hi, maybee you guys could clear up something for me

i am currently designing a system that consists of a shaft, driven by a sprocket and chain from a geared motor.

the shaft has a gear pinion at each end driving a linear rack.

I have worked out the power required by a pinion from its pitch diameter and its rotating speed, ( power = torque x rpm) however, I am unsure as to whether the power from each gear pinion would need to be added to arrive at the required input power of the shaft,

in other words, for a shaft, is the sum of all power take-offs equal to the power input? ( disregarding inefficiencies etc)

cheers,

LSM77

 

[ivymike]

unless your shaft stores an amount of energy worth considering...

 

[panduru]

As I see it, lsm77 would like to know if it is one or both PTO pinions to be taken into account to determine the motor power.

The answer would be Yes - the load is distributed between the two pinions, hence the power is the sum of the two.

However, you must bear this point in mind also while deriving the individual pinion loads/ power requirements.

All the best.

 

[sumech]

@Ism77,
yes the total power input will b equal to total power take-off, no matter at how many locations u take off the power, but one thing have to be kept in mind that is friction losses will be more as it will occur at two locations.