Hello maypot
The 638 volts quoted for the rotor voltage is the open circuit rotor voltage and is used to calculate the resistance required in order to design a suitable starter for that machine.
Unless you operate either open circuit or with a very high value of resistance in the rotor circuit, you should never get anywhere near that sort of voltage.
The important issues with rotor resistance starters is that the torque curve is modified by the value of ther resistance. If the final stage resistance is too high, the torque peak will occur at too low a speed and this will result in a high current when this resistance is bridged out.
In your case, your motor has a higher voltage and lower current than the starter that you are wanting to use. The major issue with this is that the initial resistance may be too low and you may find that your initial start current at zero is higher than desirable.
Other than that, in my opinion, you should not have a problem, depending on the load that you are starting.
Remeber, that the secondary starter has to absorb the full speed kinietic energy of the load during start. The starter must, in addition to providing the right resistance values, have sufficient thermal mass to absorb the energy without causing problems.
Best regards,
Mark Empson