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Roller Chain

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wangp1283

Automotive
Oct 19, 2004
56
I need an indepth analysis of the roller chain dynamics. It's really hard. Not even the mechanical engineering books I've tried have much on the dynamics and detailed analysis of a roller chain. Most of it is on gears. Anyone know of any good sources?

Well my question is this. In my design, I have a sprocket that drives a roller chain. However, the chain doesn't wrap around the sprocket. Rather, it's more similar to a rack and pinion system. I can't use a rack and pinion because the system needs to be flexible.

Are there any forces (separation forces) between the roller chain and the driving sprocket? I know in gears the separation force is F * tangent of the pressure angle, where F is the transmitting force.

What about for a linear roller chain and a sprocket?

Thanks.
 
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I looked in my copy of "CHAINS FOR POWER TRANSMISSION AND MATERIAL HANDLING" and they don't go into any mathematical detail on forces for the drive you want. But if you are so inclined you can get what you want from the general equations. I still recommend the book.
 
In an normal sprocket/chain drive the link rotates around the leading pin until the trailing roller bottoms in the sprocket. The chain lifts this roller to the tangent of the chainline and sprocket pitch radius. This causes a chordal motion in the chain that limits high speed service. In your design, if you fix the chain in a straight line tangent to the pitch line the roller will only bottom at the tangent point and roll up the tooth profile as the pin moves past centre. This will cause the next roller to contact the sprocket high on the tooth form, roll down to the bottom and back up which will load the teeth much more. It also causes a change in speed of the sprocket or chain with each roller contact.
Depending upon the speed you might need slipper pads or guide sprockets to keep the chain line below the pitch line of the sprocket. At least to the perpendicular line between two rollers in simultaneous contact with the sprocket.
You should be able to figure the separating force from the angle of the tooth profile at the roller contact point.
 
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