TyVan07
Mechanical
- May 26, 2008
- 17
thread404-305627
So the thread above is closed and last edited 2 years ago but didn't seem to draw any conclusions. I have looked for the answer to this question before to no avail, until now! Hopefully I save someone hours of prowling the internet for this...
Shigley's Mechanical Engineering Design, 8th Ed. p.827 Eqn. 16-28 gives torque transmitted with Force, Diameter and friction coefficient as variables.
T = (F*f/3)*(D^3-d^3)/(D^2-d^2)
F = Force applied
f = Friction coefficient
D = Outer diameter
d = Inner diameter
The derivation from Eqn. 16-27 is T = 2*pi*f*p*int(r^2,r,d/2,D/2) where p is pressure. (Don't know how/if you can use math symbols on eng-tips). int = integration
Hope this helps,
Tyler
So the thread above is closed and last edited 2 years ago but didn't seem to draw any conclusions. I have looked for the answer to this question before to no avail, until now! Hopefully I save someone hours of prowling the internet for this...
Shigley's Mechanical Engineering Design, 8th Ed. p.827 Eqn. 16-28 gives torque transmitted with Force, Diameter and friction coefficient as variables.
T = (F*f/3)*(D^3-d^3)/(D^2-d^2)
F = Force applied
f = Friction coefficient
D = Outer diameter
d = Inner diameter
The derivation from Eqn. 16-27 is T = 2*pi*f*p*int(r^2,r,d/2,D/2) where p is pressure. (Don't know how/if you can use math symbols on eng-tips). int = integration
Hope this helps,
Tyler