Jul 20, 2012 #1 mhpatel Chemical Joined Jan 31, 2012 Messages 3 Location US Hi Please help. I want to calculate how much steam required to evaporate 27,000 kg/hr water. Feed: 60% Water, 40% CaCl2 flowrate: 70,000 lb/hr Product: 40% Water, 60% CaCl2 Steam condition: 23 Barg steam Thank you
Hi Please help. I want to calculate how much steam required to evaporate 27,000 kg/hr water. Feed: 60% Water, 40% CaCl2 flowrate: 70,000 lb/hr Product: 40% Water, 60% CaCl2 Steam condition: 23 Barg steam Thank you
Jul 20, 2012 #2 TD2K Chemical Joined Jan 11, 2002 Messages 2,629 Location US I think you'll have more than 60% CaCl2 if you evaporate 27,000 kg/hr of water out of a feed stream of 70,000 lb/hr. DOW has a nice handbook on CaCl2 that you can download off the Internet. That and your steam tables should give you what you need. Upvote 0 Downvote
I think you'll have more than 60% CaCl2 if you evaporate 27,000 kg/hr of water out of a feed stream of 70,000 lb/hr. DOW has a nice handbook on CaCl2 that you can download off the Internet. That and your steam tables should give you what you need.
Jul 22, 2012 #3 HEC Mechanical Joined Aug 12, 2001 Messages 327 Location AU Just love the mixed units, imperial and metric. A minor point but what is hte feed temperature and expected outlet temperature of the mixture? Mark Hutton Upvote 0 Downvote
Just love the mixed units, imperial and metric. A minor point but what is hte feed temperature and expected outlet temperature of the mixture? Mark Hutton
Jul 23, 2012 Thread starter #4 mhpatel Chemical Joined Jan 31, 2012 Messages 3 Location US Thanks, sorry water removal rate is 27,000 lb/hr. Feed temperature is 45 C. The outlet temperature is not fix. Regards, Madan Patel Upvote 0 Downvote
Thanks, sorry water removal rate is 27,000 lb/hr. Feed temperature is 45 C. The outlet temperature is not fix. Regards, Madan Patel