ddkm
Chemical
- Nov 9, 2005
- 94
Given a known quantity of gas, say in kg, how do we convert this to "Normal m3"?
I'm quite sure I know this, but just wanted confirmation from you guys.
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My take on this is as follows, rightly or wrongly:
Using Ideal Gas Law PV=nRT:
we have PV=mRT/M
where m = mass of fluid
M = MW of fluid
Thus, the "normal" m3 of the fluid would be:
V = (mRT) / (MP)
where P = pressure at atmospheric (i.e. 101325 Pa)
and T = the "standard" temperature of 25ºC or 298.15K
IS THIS RIGHT?? Any comments? Thanks all.
---engineering your life---
I'm quite sure I know this, but just wanted confirmation from you guys.
-----------------------
My take on this is as follows, rightly or wrongly:
Using Ideal Gas Law PV=nRT:
we have PV=mRT/M
where m = mass of fluid
M = MW of fluid
Thus, the "normal" m3 of the fluid would be:
V = (mRT) / (MP)
where P = pressure at atmospheric (i.e. 101325 Pa)
and T = the "standard" temperature of 25ºC or 298.15K
IS THIS RIGHT?? Any comments? Thanks all.
---engineering your life---