RobertEIT
Structural
- Aug 18, 2008
- 63
I am looking at AISC-13th 16.1-68 sect.G4, it says in calculating rectangular HSS nominal shear strength, the area Aw=2ht, where h shall be taken as the corresponding outside dimension minus three time the thickness.
Now look at AISC Example G.4 (Example page G-8), "h" is taken as:
h=d-2*(3*tw)=6-2(3)0.349)=3.91 in. (note: there is a "2" multiplies 3 times of the thickness)
Look at another AISC Example H.5c(page H-15), "h" is taken as:
h=d-3*tw=6-3(0.233)=5.3 in. (note: there is just "1" multiplies 3 times of the thickness)
These two examples, which one is correct, which one is wrong?
Thanks.
Now look at AISC Example G.4 (Example page G-8), "h" is taken as:
h=d-2*(3*tw)=6-2(3)0.349)=3.91 in. (note: there is a "2" multiplies 3 times of the thickness)
Look at another AISC Example H.5c(page H-15), "h" is taken as:
h=d-3*tw=6-3(0.233)=5.3 in. (note: there is just "1" multiplies 3 times of the thickness)
These two examples, which one is correct, which one is wrong?
Thanks.