question about a composite shaft under torque

[anatino]

There's a composite shaft, the white space is the weld and its thickness is negligible.
and there's a distributed torsional moment t, applied along the full length of the composite shaft.
That's fine, but the formulas they got for 11b, was: -Ts + T_s(x) = 0
Ts is the reaction force of the inner tube (cause the shaft is clamped to a bar)
and T_s(x) is the internal force on the inner tube.

Now my question is, why didn't they include the distributed torsional moment? Does the fact that its an inner shaft mean it doesn't experience distributed loads? and only the outer shell does?

here's the picture of the actual thing:

and as you see, 12a has tx, meaning the full distributed load tx is included on the outer hollow tube but none in the inner solid one...

 

[GregLocock]

How owuld you apply a distributed external torque to an inner shaft?

 

[goutam_freelance]

If both the inner and outer shafts are twisted at the same angle, then there will be a division of torque between the two depending on their torsional rigidities. Total torque will be the sum of the inner and outer shaft torques.

The mechanism of distributed torque to the inside of the outer shaft is not clear. However, the total torque will be shared between the two as above.

 

[GregLocock]

It seems a very odd problem, have you left some preamble out?

 

[anatino]

Hey guys I ended up figuring it out, but yeah essentially it was wrong cause in the main question they said that these 2 materials aren't glued together, but only at x = L they are both stuck to a plate. Meaning the torsional moments only apply to the upper hollow cylinder and at x = L they are both twisted