kayro
Mechanical
- Jan 13, 2017
- 1
Can't convince myself I'm doing this right.
0 - 25lb load cell
10V excitation
Rated Output: 2mV/V
nonlinearity: .10%
nonrepeatability: .05%
hysteresis: .10%
zero balance: 1.0%
E* = sqrt(.002^2 + .001^2 + .002^2 + .02^2) = 0.02 mv/V accuracy
*those numbers represent error % * Rated Output in mV/V
if I have 25lb/20mV full output at 10V excitation,
then my accuracy in lb is (25lb/20mV)*.02 mV/V = +/- .25 lb accuracy.
Disregard my amp and DAQ for the time being, I am just trying to assess the sensor. Thank you for any feedback, I can never straighten this out in my head.
0 - 25lb load cell
10V excitation
Rated Output: 2mV/V
nonlinearity: .10%
nonrepeatability: .05%
hysteresis: .10%
zero balance: 1.0%
E* = sqrt(.002^2 + .001^2 + .002^2 + .02^2) = 0.02 mv/V accuracy
*those numbers represent error % * Rated Output in mV/V
if I have 25lb/20mV full output at 10V excitation,
then my accuracy in lb is (25lb/20mV)*.02 mV/V = +/- .25 lb accuracy.
Disregard my amp and DAQ for the time being, I am just trying to assess the sensor. Thank you for any feedback, I can never straighten this out in my head.
