Katmar,
You have hit the essence of the reason for specifying a target velocity, but the actual numbers that the OP mentioned come from a specific empirical API erosional velocity equation (it is early in the morning and I'm not up to looking up which API document it is in):
v=100 ft/s / (fluid density in lbm/ft^3)^0.5
Using all fps units and then converting the answer to mks I get 3.9 m/s for pure water. If I convert 100 ft/sec to 30.40 m/s and 62.4 lbm/ft^2 to 1,000 kg/m^3 then the equation gives me 0.964 m/s. Like many empirical equations, the units are coincidental (dividing a velocity by a density does not yield a velocity) and it doesn't translate well, but the 1 m/s comes from translating the input and the 3 m/s comes from translating the output.
Another example of an empirical equation that doesn't translate is the rule of thumb that hydrotest water in bbl/thousand ft is about equal to the ID of the pipe in inches squared. This equation happens to work even though the units look odd (in^2^ft does not equal bbl). For example, if I have 10,000 ft of 8 inch ID pipe, the actual internal volume is 622 bbl, the rule of thumb gives you 640 bbl. If I convert the output then I need 101,751 L, if I convert 8 inches to 203 mm; 10,000 ft to 3048 m; and 1000 ft to 30.48 m then I get 412,902 L. You really have to be careful with empirical equations.
Penpipe,
It is a really bad idea to chastise someone with the wrong information. The word he was looking for was "velocity" which is "speed" plus a direction vector. "Rate of flow" is generally taken to mean "flow rate" which is an ambiguous reference to either "mass flow rate" or "volume flow rate". His use of "speed" was far less ambiguous than your use of "rate of flow".
David