BobPE, I'll try.
The author claims that calculating the "loss coefficient" K
f in the irreversible energy dissipated by friction, e
f = [Σ]K
fi V
i2/2, by using three constants based on the type of fitting, its diameter and the Reynolds number, which also depends on flow rates, shows an excellent fit.
He states that other (obsolete) methods for estimating the loss coefficient, such as those based on tabulated single values, or even those given by Crane which are based on the friction factor of fully turbulent flows on Sch 40 clean pipes, and on the (L/D)
eq of the fitting, fall short because they use one or two constants to characterize the loss coefficient and do not reflect the full influence of the Reynolds number.
The author submits a comparison on the flow rates for water -estimated on a particular example for Reynolds number ranging from 393 to 13,100 and pipe sizes from 1-in. to 12-in.- showing under- and over-predictions resulting from using other procedures vs his proposal.
His 3-K equation appears to have a very good statistical accuracy of the fit as measured by r
2.
The value of the dimensionless loss coefficient is obtained from a formula such as:
Kf = Km/NRe + Ki(1 + Kd/D0.3)
The author provides formulas, tables and graphs for the constants in this formula.
The flow rate is calculated from
Q = 1.111 D2[g[Δ]Z/([Σ]Kfi + 1.5)]1/2
Where:
Q = flowrate, CFS
[Δ]Z = change in elevation, ft
D = diameter of pipe, ft
g = gravitational acceleration 32.2 f/s
2
K
fi=loss coefficient for each of the pipe system elements, dimensionless.