"no-one has answered where the horizontal reaction comes from"
yes they did, pushing against friction of the pivot and possible air resistance
No argument with that, but some are arguing (I now think correctly) that you don't need friction and/or air resistance.
"Everyone agrees that with a rigid rod it's possible to generate horizontal movement. A bicycle operates in a similar way in principle."
a bicycle would be like pushing off the ground on a swing, you are fixed to the pivot in all axis and pushing the pedal/swing. Not touching ground on a swing you are only fixed in the vertical axis.
OK, the bicycle analogy was a bit of a stretch, but the point I was making was that there is a fundamental difference between working on a rigid rod (to which you can apply a torque) and a chain or rope.
"The question where people still differ is what happens on an idealized swing in a vacuum with a frictionless rope of zero flexural rigidity."
My instinct says you can't start the pendulum.
" how do the kids move their centre of mass with no reaction force to start with?"
they don't
This is the question I wanted answered, and I think that Greg has now answered it.
With the no friction/ no air/ flexible chain and no initial movement, whatever you do the centre of mass of swing + rider will stay exactly where it started; under the top pivot, but the bottom end of the rope will not necessarily stay under the pivot, and as soon as you have some inclination in the rope you have a source of a horizontal reaction, and the ability to move your centre of mass.
I was arguing (to myself) that any offest between the bottom of the rope and the centre of mass will result in a rotation, and this will keep the bottom of the rope below the top, and above the centre of mass. What I missed was that will take time, so if some part of the swinger is moved sufficiently quickly, this will generate the required inclination of the rope, even though the centre of mass doesn't initially move.
Doug Jenkins
Interactive Design Services