Hi
Check the head H and flow Q (pump nameplate) and type of pumped fluid, you will get the power at shaft using P=density x 9.81 x Q x H / efficiency.
Assume 70-75 % efficiency not irrealistic, except if wastewater submersible pump could be far lower sometimes (40-50%?).
Then the motor should be sized according to such power plus margin (+8 to +10%?)
Once you get the rated power of the motor, you need to account for motor efficiency (96%) and then you should come up with some figure about the electrical power.
With such power you should fall in some normalized range :
110 volts to 690 volts are often classified as low voltage units let say from 0.2 kW up to at least 750 kW.
Medium voltage at 3 kV (50 Hz) or up to 10 kV typically designed for use with motors rated to 375 kW and above.
this is just to tentatively help you have some guess...
Rgdrs
Wimple