AgSilver
Chemical
- Nov 16, 2011
- 7
In front of me is a pump curve with some specs.
Duty flow: 1600 gpm
Duty head: 120 psig
NPSHR: 11.3 psi
Now that I have a different flow rate, I want to check if this pump is still ok. The only information I have is that the water tank is exposed to atmospheric pressure, its elevation relative to the pump, and the operating temperature (to get the relevant vapour pressure). Since I know nothing about the velocity and piping configuration, I decided to lump (Hv - Hf) = K*Q^2.
NSPHA = Hatm + Hz + Hv - Hf - Hvp
Hatm = head developed from atmospheric pressure
Hz = elevation head (surface of liquid is above pump)
Hv = velocity head
Hf = friction losses
Hvp = vapour pressure of water at specified temperature
Thus,
(120 psig) + 14.7 psi = 14.7 psi + 13 psi + K*1600^2 - 0.26 psi
The 13 psi comes from the fact that there is 30 ft of head (water) and the 0.26 psi is the vapour pressure of water at the operating temperature.
Rearranging the above equation,
I have K = 107.25/1600^2
Again, since I know nothing about the piping configuration, I will assume that K is the same at the different flow rates.
To find to the new NPSHA for a different flow rate,
NPSHA = 14.7 psi + 13 psi + K*(Q/1600)^2 - 0.26 psi
Am I doing this wrong?
Duty flow: 1600 gpm
Duty head: 120 psig
NPSHR: 11.3 psi
Now that I have a different flow rate, I want to check if this pump is still ok. The only information I have is that the water tank is exposed to atmospheric pressure, its elevation relative to the pump, and the operating temperature (to get the relevant vapour pressure). Since I know nothing about the velocity and piping configuration, I decided to lump (Hv - Hf) = K*Q^2.
NSPHA = Hatm + Hz + Hv - Hf - Hvp
Hatm = head developed from atmospheric pressure
Hz = elevation head (surface of liquid is above pump)
Hv = velocity head
Hf = friction losses
Hvp = vapour pressure of water at specified temperature
Thus,
(120 psig) + 14.7 psi = 14.7 psi + 13 psi + K*1600^2 - 0.26 psi
The 13 psi comes from the fact that there is 30 ft of head (water) and the 0.26 psi is the vapour pressure of water at the operating temperature.
Rearranging the above equation,
I have K = 107.25/1600^2
Again, since I know nothing about the piping configuration, I will assume that K is the same at the different flow rates.
To find to the new NPSHA for a different flow rate,
NPSHA = 14.7 psi + 13 psi + K*(Q/1600)^2 - 0.26 psi
Am I doing this wrong?