shup0739
Mechanical
- Feb 26, 2003
- 20
Hello All,
I am trying to size a steam trap for a main steam header.
I have a 165 psig steam header and would like to put a trap at the low point. I've done some calculations and my load comes out to less than 1/2 lb/hr. I'm not sure if that really makes sense, I was anticapating more but I might have made a mistake in my calculation can someone please tell me what I'm doing wrong...here is my calculations:
A:External Area of Pipe, ft^2: 1.178
U:Heat Transfer Factor, Btu/ft^2/F/hr=0.343636364
Delta T:Temperature Diff(steam temp - air temp), F=304.9992
E: 1 minus Efficiency of Insullation= 0.1
H: Latent Heat of Steam, Btu/lb = 844.9
S: Safety Factor(End of Header)= 3
Q :Condensate Load, lbs/hr= A*U*(DELTA T)*E*S/H = .04383884
This is telling me that I will anticapate about 4 % of a pound of condensate. which comes out to about a pound per day.
Thats not much at all.
I have crane tech 410 but I can't seem to find anything different.
Regards,
Sam
I am trying to size a steam trap for a main steam header.
I have a 165 psig steam header and would like to put a trap at the low point. I've done some calculations and my load comes out to less than 1/2 lb/hr. I'm not sure if that really makes sense, I was anticapating more but I might have made a mistake in my calculation can someone please tell me what I'm doing wrong...here is my calculations:
A:External Area of Pipe, ft^2: 1.178
U:Heat Transfer Factor, Btu/ft^2/F/hr=0.343636364
Delta T:Temperature Diff(steam temp - air temp), F=304.9992
E: 1 minus Efficiency of Insullation= 0.1
H: Latent Heat of Steam, Btu/lb = 844.9
S: Safety Factor(End of Header)= 3
Q :Condensate Load, lbs/hr= A*U*(DELTA T)*E*S/H = .04383884
This is telling me that I will anticapate about 4 % of a pound of condensate. which comes out to about a pound per day.
Thats not much at all.
I have crane tech 410 but I can't seem to find anything different.
Regards,
Sam