I can't say that I'm an expert in this area but there is an equation found in ASHRAE that might apply to this situation.
DP = (Q/2610*A))^2. Where dp is the diffential pressure (0.1" in this case), Q is the cfm, A is the area of leakage.
You can solve for Q to find the cfm, but you need to know what your Leakage area is. The cfm required to maintain a certain differential pressure is dependent on construction type.
I know when designing negative pressure rooms in hospitals the cfm required to maintain a .05" pressure can range from 100 to 500 cfm difference between exhaust and supply depending on how tightly sealed the doors and ceilings are.
I also believe somewhere in ASHRAE they recommend no larger than about a .03" WC across a door so that it isn't too difficult to push open.
This probably doesn't completely answer your question, but maybe its a start.