Hello, first of all and again, many thanks for your help.
This is still in concern with an ammonia tank. I have done the calculations below in response to the following question and with the help of 25362, dcasto and Txiceman in my last message.
“Demonstrate the mechanical resistance of a NH3 vessel considering it’s filled to the maximum level authorized at -3°C and a temperature increase to the ambiant temperature (I took 50 °C).”
The problem is that my client says that the filling rate is around 65% and I find 82%.
The input data that he gave me are :
Maximum authorized mass = 48899 kg
Vessel volume = 92,283 m³
Filling rate : 65%
My calculations :
We have : Vtotal = 92,263 m³ = Vliq + Vgaz and Mtotl = Mliq + Mgaz = 48899 kg
At -3°C, 1m3 of NH3liquid weights 642,66 kg and 1m3 d'NH3gaz weights 3,1038 kg,
Since
Mliq = Vl x 642,66
Mgaz = Vg x 3,1038
Then Mass total = Vl x 642,66 + Vg x 3,1038
Vg = 92,263 - Vliq
Mass total = Vl x 642,66 + (92,263-Vl) x 3,1038
Vl = (Mass total – 3,1038 x 92,263) / ( 642,66 – 3,1038) = 76,01 m³
Thus Vg = 92,263-76,01 =16,25 m³
And the filling rate equals to 82,38% and the pressure is 3,83 bar.
Using the same method, I find that at 50°C the filling rate is about 94% and the pressure = 20,34 bars.
Is is possible that 48899 kg of ammonia at -3°C corresponds to a filling rate of 65%?