Well, if you know the K values then the pressure drop for a particular fitting would be
K*Rho*V*V/2g
where
rho= density in lb/Ft^3or Newtons/M^3
V fluid velocity Ft/sec or M/sec
g= gravitational constant 32ft/sec^2 or 9.8M/sec^2
The answer is in lb/ft^2 or Newtons/M^2 which can be converted to psi or whatever you Brits use.
For example,
if a globe valve has a K factor of 1.5 , then for a 1 inch pipe size handling 8 gpm of water which corrresponds to 2.5 ft/sec, the
V^2/2g called the velocity head is
.097 feet and at water's density 62.4 and K=1.5 the pressure drop across the valve is
1.5*62.4*.097=9lb/ft^2=.06 psi
I imagine that if you use the mfr K value, they want to make sure that you are accepting that value translated to psi drop as a check. So enter any reasonable acceptable value, say .1 psi and see what the program asks. It may say there is a discrepancy and tell you why. I just don't know.