would like to know how to compute the pressure drop through a reducer from 20 inches to 12 inches if the inlet of the reducer has 195 centrigrade 77t/hr of crude oil column overhead vapour
There is very little published data for standard pipe reducers. Hooper (Chem Eng, Nov 7, 1988, pg 89-92) says reducers give very little resistance when flowing from large to small, but are effectively sudden expansions when flowing from small to large.
In the reduction mode Hooper's equation is
K = (0.1 + 50/Re)( (D/d)^4 - 1 )
where
Re is based on inlet (large) diameter
D is inlet (large) diameter
d is small (outlet) diameter
A conical tapered reducer would give a higher K value than this.