Suggestion: The following was posted in this Forum in the past, and pertains to this thread:
Can anyone please give me the formula for calculating the line currents taken from the starter for a 3-phase motor if the same motor is connected in
(a) star/wye connection
///Iy=Pwatt,y/(sqrt3 x Vline-line x eff x pf)\\(b) delta connection
///Id=Pwatt,d/(sqrt3 x Vline-line x eff x pf)\\The common formula is P = Root 3 x V x I x P.F. x Efficiency
But is that for a star or delta connection?
///Yes, if properly applied. Specifically,
y-motor connection:
Pwatt,y=sqrt3 x Vline-line x Iline,y x pf x eff
d-motor connection:
Pwatt,d=sqrt3 x Vline-line x Iline,d x pf x eff
The difference is in Iline,y and Iline,d
Iline,y=(1/3) x Iline,d
since
the voltage across the y-connected motor winding will be Vline-neutral=(1/sqrt3) x Vline-line
and the current for d-connected motor winding will be
Id=Iline,d/sqrt3
Considering that the motor winding impedance Z is constant from y-connection to d-connection, then:
Ilind,d=sqrt3 x Id
Iline,y=Vline-neutral/Z
Id=Vline-line/Z=sqrt3 x Vline-neutral/Z=sqrt3 x Iline,y
hence,
Iline,d=sqrt3 x Id=sqrt3 x sqrt3 x Iline,y = 3 x Iline,y
Therefore,
Pwatt,d=3 x Pwatt,y
\\
There are tables of typical motor currents available.
///Usually, a manufacturer catalog provides tables with specific motor currents. The generalization is usually obtained by motors application engineers or designers.\\Are those currents for star or delta?
///This has to be properly stated in terms of the motor winding to avoid any ambiguity\\ e.g. 15 kW 400V 28A,
///This can be for d-connected motor or y-connected motor. The motor connection must be known, if needed, to avoid ambiguity.\\ 1.1kW 400V 2.5A
///The motor connection must be known, if needed, to avoid ambiguity.\\I have an ABB motor with 2.2 kW 380-440V star/wye 4.9A on the nameplate.
///This motor appear to be suitable for the motor terminal voltage range 380V to 440V and it is star/wye connected.\\But the test sheet on the ABB web page says 400V delta 4.85A 2.2 kW; 400V star 6.3A 3kW
///This is an inconsistent rating for the motor since the delta connection at 400V shows the smaller current, 4.85A with respect to the y-connection at 400V current, 6.3A.\\The nameplate says star - the test sheet says delta. How do I connect it?
///If the test sheet does not accompany the motor and overrides the nameplate data, then the motor nameplate information governs.\\I contacted ABB but am waiting for a reply.
///The confirmation from ABB is recommended because of the posted ambiguity.\\I have seen statements that "small" motors are connected in star.
///There are many statements as this one. The y-connected motor with three leads in the terminal box is someone simpler to produce, has smaller voltage stresses etc.\\One said less than 4kW, another said less than 11kW.
///This can be.\\Does this vary with manufacturers?
///Probably.\\What happens if a small motor is connected in delta?
///If provisions are made in the motor terminal box, it is understood that the manufacturer provided the provisions for y-connection and delta-connection. However, the y-connected motor should then have shaft load reduced to 1/3 of delta connection. However, the motor voltage rating is important. It is not possible to connect y-connection Vline-neutral voltage, e.g. designed for 220V, motor to 380V Vline-line motor since the motor winding would burn. Remember that the motor winding impedance is constant equal to Z.\\