Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations cowski on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

PID Integral Time/Derivative Time

Status
Not open for further replies.

sreid

Electrical
Joined
Mar 5, 2004
Messages
2,127
Location
US
This is a historical question. In the standard ISA PID Equation (and usually in older texts/papers), Ti is in the equation as 1/Ti and Td is, well Td. What was the reasoning for Integral Time to be a 1/x function?
 
Integral units can be either minutes or repeats per minute, either of which is the reciprocal of the other:
2 rpm = 0.5 min.

So the 1/Ti is probably in units of repeats per minute, whereas Rate is usually in units of minutes.

I'm too young to know which units were initially used for integral, minutes or repeats per minute, but I'm sure someone here knows.

Dan
 
Simple
The integrator integrates error over time. The units are error_units x time. When one divides by the integrator time constant the result is now error_units. The derivative term multiplies the derivative of the error by the derivative time constant. error_units/time x time = error_units. The error units for each term are then summed and multiplied by the controller gain which has units of control_output_units/error_unit.

Peter Nachtwey



 
What has been said above is true. But is it the real *reason* for this convention?

I have, myself, always thought that it reflects the use of Laplace transforms where integral is 1/s and derivation is *s.

It can also simply be the fact that "integral gain" is proportional to 1/Ti while derivative gain is proportional to Td, which is in line with Peter's thinking.

Gunnar Englund
--------------------------------------
100 % recycled posting: Electrons, ideas, finger-tips have been used over and over again...
 
I was trying to keep it simple. For those of you in the s domain...

PID(s)=K(1+1/(ti*s)+td*s)

Think of s as a frequency or 1/time then the frequency times time = 1 and the gain still has units of control_output_units/error_unit).





 
Thanks PNatchwey. I had always assumed the Laplace reasoning but the dimentional analysis had eluded me. The servo industry almost always uses gain values Kp, Ki, Kd) so that's what I'm use to.
 
Thanks PNatchwey. I had always assumed the Laplace reasoning but the dimentional analysis had eluded me. The servo industry almost always uses gain values Kp, Ki, Kd) so that's what I'm use to.
Then

Kp=K
Ki=K/Ti
Kd=K*Td

I too am a motion person. I don't understand why the process industry uses terms like reset or repeats. I never have understood what is reseting or repeating.

I still think in terms of Kp/Ki=Ti since this is a useful number for figuring out how long it will take the integrator to wind up to a steady state value. ( 5 x Ti )



 
History - or Pseudo History
I once heard that PID control originated with battle-ship gun controls in time for use during WWII. The process industry uses the terms that were applied by manufacturers of pneumatic PID controllers.
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top