JohnDeereSurfer ,
If i understand correctly , you have problem with the definition of (d) for the nonconstrained case. ( English is not my first language so, if my interpretation does not answer to your question , we may work an examle ).
- the (Equation 18-1) is closed form equation which could be solved mit iteration or with charts ( pls look attached doc. at my first post ), and could be solved with the following steps ;
- without knowing ( d ) an initial assumption is necessary . since the equation is valid for max . d= 12 ft, assume d=12 ft ,
- calculate the S1 = Allowable lateral soil-bearing pressure as set forth in Section 1806.2 based on a depth of one third
the depth of embedment . Look TABLE 1806.2, e.g . Assume material class 4.( Sand, silty sand, clayey sand,silty gravel and clayey gravel ) TABLE 1806.2, S1 will be 4*150=600 (psf).
- calculate the required (d) for this value , and find say 9.0 ft,
- repeat the second step till d= d previous calculated , ( 2-3 iteration would be sufficient )
- or use alignment chart
I hope this respond answers your problem.
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