OK.
Technical references may easily be found in the internet.
Since the scrubber is small, have you considered using just water? If you simply dissolve the gases in water you'd probably absorb much more CO
2 than SO
2 because of their relative proportions in the gas (divided by their respective Henry Law constants). For example, if the relative volume fraction of CO
2 /SO
2 in the gas is, say, 190:1 the mol fractions absorbed in water @ 30
oC, would be: (190)(50)/(1900) = 5. Five times more CO
2 than SO
2.
The reactions with water:
CO
2(gas) <-> CO
2(dissolved); +H
2O<->H
2CO
3<->H
+ +HCO
3-
SO
2(gas) <-> SO
2(dissolved); +H
2O<->H
2SO
3<->H
+ +HSO
3-.
The right concentration of H
+ in solution that drives the first reaction to the left while driving the second to the right happens at 10
-4 to 10
-6 mols per liter (pH= 4-6). This pH is not achievable with NaOH solutions. NaOH solutions (pH>7) would absorb more CO
2 than SO
2 at 30
oC.
To remove SO
2 without absorbing CO
2, the scrubbing solution should be a
weak acid. That's the reason I suggested you visit the other thread.
Industrial-size solutions consider using soda ash (sodium carbonate) or bicarbonate which are cheaper and can be regenerated. A typical reaction would then be:
Na
2CO
3 + SO
2 -> Na
2SO
3 + CO
2 for the scrubber
And in the holding tank one may regenerate the sodium carbonate with calcium salts in a reaction such as:
Na
2SO
3 + CaCO
3 + 0.5 O
2 -> CaSO
4(Gypsum) + Na
2CO
3
then to a thickener for precipitation and separation of calcium sulphate (with a flocculating agent), while the supernatant liquid would be reused in the scrubber. Some carbonate is lost in the cake, and some calcium would be retained in solution but in sufficiently low concentrations not to form solids in the scrubber.
Yours is a apparently a small outfit so my suggestion is you heed PeterAB's advice.
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