Folks-
I have a need to deform a straight, .08"x.20"x1.38" strip of aluminum 1100-O into a U-shape (around a box-shaped mandrel). The inside dimension of the U-shape (the outside dimension of the mandrel) is .57". I have data that indicates that the yield strength is nominally 3.5ksi and that the UTS is nominally 13ksi. Would it be wrong to make a linear-elastic assumption to calculate the force required to form the U? What force do you come up with if the forces are applied laterally and in the middle of the "beam"? This is not an academic problem! It has to do with production personnel installing a retention shim into an assembly.
Thanks in advance.
Tunalover
Tunalover
I have a need to deform a straight, .08"x.20"x1.38" strip of aluminum 1100-O into a U-shape (around a box-shaped mandrel). The inside dimension of the U-shape (the outside dimension of the mandrel) is .57". I have data that indicates that the yield strength is nominally 3.5ksi and that the UTS is nominally 13ksi. Would it be wrong to make a linear-elastic assumption to calculate the force required to form the U? What force do you come up with if the forces are applied laterally and in the middle of the "beam"? This is not an academic problem! It has to do with production personnel installing a retention shim into an assembly.
Thanks in advance.
Tunalover
Tunalover
