Main Force Wind Resisting System

[Civil57]

Question? Working on a
40ft by 100ft metal building with W12 X19 cols 20ft on center and C6 x225 x14Ga grits. rafters are W12X19.
26 Ga wall metal roof and wall panels
23 ridge ht
21 mean ht
After I have calculated the wind and component and cladding loads how do I check the design to insure it meets the loading.?

Thks

 

[JAE]

That is a very broad question. You take the C&C wind loads and apply them to the girts (wind based on girt tributary area) - then check the girts in bending and shear. Then take that end reaction and design the girt-to-column connection.

Then re-calculate the C&C wind loads based on the column's tributary area. If the tributary area is large enough, use the MWFRS loads instead. This would also include roof wind (uplift for flatter roofs) and column applied dead and roof live/snow loads. Design the column for axial, bending and shear per your applicable steel code.

I'm stopping here - but you should know how to do all these things if you are a structural engineer. Is there a more specific question?

 

[woodman88]

You need to follow the building code and/or standards that apply to your building. Go read them. If you have any questions about how to do it, please give us the question and the code/standard section you are looking it. I am sure someone here will be able to point you in the right direction.

Garth Dreger PE - AZ Phoenix area
As EOR's we should take the responsibility to design our structures to support the components we allow in our design per that industry standards.

 

[JedClampett]

Your question is titled, "Main Wind Force Resisting System" but the body of the question only mentions component and cladding forces. So I start out a little confused.
Main Wind Force Resisting Systems is defined in ASCE 7. Basically, these are the components that provide global resistance to a high wind event like shear walls, rigid frames, braced systems, etc. C and C are the individual pieces like girts, purlins, doors etc. In general, you need to address both because the larger the item, the smaller the wind load. Wind is uneven, with gusts, concentrations and other effects. So a window might see a much larger pressure than the wall it's mounted on.
From the tone of your question, I think you need to ask someone else in your place of employment how to do this. These threads are OK for specific questions, but it's hard to convey entire building designs.
As Garth said, hone in on your questions, maybe we can help.

 

[MiketheEngineer]

I think you need to get with someone to show you how and why. This is not a trivial structure.

 

[ToadJones]

seems hokey.
I take it that this an existing building?