David,
Your question intrigued me, so I did some online searching to find information about Platonic solids.
Among the sites that had pertinent info, and which turned out to be the most informative was...
(There's also an article about the Icosahedron on Wiki.)
After a while, I figure out how to construct the planes that josephv alluded to. Then, it's a matter of modifying the values of Phi, & phi and 1 which are given on those pages for a UNIT Dodecahedron and which result in a dimension of sqr(3) as the distance from any vertex to the origin.
There are very good explanations as to how the values were obtained.
The new values for the 3" sphere are decreased by the ratio of the radius of your sphere (1.500") to the sqr(3) or 1.732+; giving a factor of .866025404
Using Excel, I set these up so that I could easily copy and paste the values into the point co-ordinates in a 3-D sketch in SW.
After placing a 3" sphere in a new Part, and all 20 points (vertices) were in the 3-D sketch, I Inserted planes that connected sets of 5 points to form a pentagon, then Extrude-Cut outward from the sphere and at a 32 angle outward.
(This has to do with the "dihedral angle" that is formed between any adjacent interior faces of the pentagons.)
It may be easier to just use the Plane for cutting; however, see below.
By the way, none of the Cartesian coordinates that are given actually gives the 1.5" dimension in Top, Front, or Right planes, but it is in fact, an indirect result of placing the coordinates given, and can be varified before proceeding with all the vertices.
One thing that became obvious, is that only 4 adjacent pentagons were actually needed; just have establish an Axis and Circular Pattern them around it. See pic.
Also, how do you plan on machining these? Looks like it might be a challenge.
Good luck, Gatz