In addition.
The same book by Crowl & Louvar gives an example of how to estimate the LFL and HFL of a mixture of air with flammable gases, based on Le Chatelier's empirically derived equation to determine if a certain mixture is flammable or not.
LFLmix = 1[÷][Σ] (yi/LFLi)
and
UFLmix = 1[÷][Σ] (yi/UFLi)
Where
y
i = mol fraction of the flammable gas i in the mixture with air
LFL
i = LFL of the flammable gas i in the mixture
UFL
i = UFL of the flammable gas i in the mixture
The authors advise us that empirical formulas like these have their limitations. Therefore, I suggest following Latexman's advice.
BTW, the lowest (roughly)
estimated LOC doesn't necessarily go with the lowest LFL. Take, for example:
Metane: LFL = 5.0. LOC = 5.0[×]2 = 10.0
Hexane: LFL = 1.1. LOC = 1.1[×]9.5 = 10.45
Ethylene: LFL = 2.7. LOC = 2.7 [×]3 = 8.1
Heptane: LFL = 1.1. LOC = 1.1[×] 11 = 12.1
Acetone: LFL = 2.5. LOC = 2.5[×]4 = 10.0