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Knurled pin torque and pull out force

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Mandrill22

Mechanical
Jul 30, 2010
113
Screenshot_20190928_112505_rayeje.jpg

Screenshot_20190928-112653_Drive_kr7jxm.jpg


It's absurd that the manufacturer (Reell) won't tell me, but I am trying to find some basic info about a knurled pin (material of the pin is very hard steel, but the specs are proprietary to the manufacturer). The insert is mounted vertically and the ends of the pin are pressed into cast aluminium. The inner housing is considered fixed. There is zero axial load support, so the pin can slide out of the one housing (design flaw?), so I am using a deep groove ball bearing to take axial load. The pin and cast pieces on the end rotate together. The inner housing provides 2 or 3 Nm of resistance. See both attached images (of they don't upload together, I'll reply with the second image immediately). There is a hard stop rotationally. I am trying to determine :

1. Pull out force in axial direction (pin sliding out of cast pieces due to hanging load). Using worst case scenario for the pin and cast pieces (let's say one cast piece holds better than the other and the knurls are relatively smooth). I know the knurls are cold drawn.

2. Torque at which the knurls would cut into the aluminium, causing failure. This is assuming the rotation is at a hard stop.
 
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Hardened steel into cast aluminum? Give it a little time and you won't be able to remove or twist it. It will seize from corrosion.


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It's made to be pressed into aluminium. I assume it's steel,but they won't say
 
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