Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations JAE on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

isentropic outlet enthalpy is not greater than actual enthalpy as the formula suggests.

Status
Not open for further replies.

Rao23

Aerospace
Joined
Apr 18, 2024
Messages
2
Location
IN
Hello Engineers,

I am designing a SCO2 Brayton cycle for my job,
as i understand, η compressor = (h2s - h1)/(h2-h1) since here we are putting energy to the system & η expander = (h2-h1)/(h2s-h1) since here we are extracting energy from the system.
when i solve the eqn, for compressor h2>h2s & for expander h2s>h2, but that's not what i see in the excel sheet which i have linked with REFPROP(a software that does thermodynamic calculations). I see for compressor it's alright, but for expander i see h2>h2s. but the real problem is the graphs we plotted (for instance: exp 1 eff vs cycle efficiency) makes sense having that enthalpy values doesn't make sense.
please clarify if i misunderstood any of the above.

Thanks in advance
Rao
 
found the answer myself. Thanks.
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top