ALREMAN
Mechanical
- Jul 21, 2010
- 21
I have a spline on a hydraulic motor that is a Flat-Root Side Fit per ANSI B92.1, 30 degree pressure angle. I am using the motor to drive a chain drive. The sprocket is a double sprocket that has two set screws, 90 degrees apart to secure it to the shaft. This is a low cycle, high torque, slow speed (<20 rpm) application. Since I am not using standard materials for the mating sprocket (SS 316), and I am exceeding the recommended max bore size for the sprocket, I am going through the stress calcs to make sure my drive will hold up. I am basing my calcs off of the Machinery's Handbook approach. I see that alignment is important and depending on what load distribution factor I choose (Km) from the table my results can change dramatically. I am looking for some guidance on how to choose the correct misalignment factor. If I take the diametrical clearance and divide that by my engagement length, I get .033"/1.60" = .021 in/in. Is this my max misalignment that I should base my load factor on? The table only goes as high as .008 in/in. Alternatively, should I select a misalignment factor for the design and use that as alignment criteria for installation? I think that a direct mounted sprocket with a side load (chain tension) will behave differently than if I had two shafts coupled together with some angular misalignment. My two set screws, when tightened down, will cause some eccentricity between the drive shaft and the sprocket center. Additionally, the sprocket will always ride on the high tension side of the shaft due to the chain. I picture this causing wobble at the end of the sprocket where the set screws are. Does anyone have some insight here?