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Interpreting circuit correctly 1
- Thread starter culloekee
- Start date
MacGyverS2000
Electrical
If 14V is applied, the input is 14V (assuming you can supply enough current).
Dan - Owner
Dan - Owner
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1
- #3
zappedagain
Electrical
14V / 5K = 2.8 mA. As long as your source can provide 2.8mA of current, you will have 14V on your line driver input. If it can't you will have a lower voltage. 5k * 1mA = 1V for example.
If you disconnect the source you will have 0V on your input. Without the 5k you would have a floating input that can easily pick up noise and give you lots of random data (chatter) on your line driver output. Unless your line driver has internal circuitry to make sure this doesn't happen.
Grounds are very important. If you 'lose' the ground connection at your line driver there is a good chance your line driver may be damaged. I know of one junior engineer who powered up a custom ASIC before making ground connections; the device was damaged beyond repair.
Z
If you disconnect the source you will have 0V on your input. Without the 5k you would have a floating input that can easily pick up noise and give you lots of random data (chatter) on your line driver output. Unless your line driver has internal circuitry to make sure this doesn't happen.
Grounds are very important. If you 'lose' the ground connection at your line driver there is a good chance your line driver may be damaged. I know of one junior engineer who powered up a custom ASIC before making ground connections; the device was damaged beyond repair.
Z
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