I was wondering if there is a way of evaluating indefinite integrals with conditions on the integral which define the constant of integration. For instance, I would like to be able to input a function, f(x) = x, and the boundary condition F(2) = 4, and receive F(x) = 0.5(x)^2 + 2. Thanks for any help in advance.
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Indefinite Integrals
- Thread starter CDR
- Start date
Here is one way on how to do it
Solve the integral of f(x) symbolically this is g(x)
set x0=2 y0=4
constant of integration C = y(0)-g(x0)
Then F(x) [red]=[/red] g(x)+ C
[red]=[/red] is the symbolic equal arrow pointing to right (Press Ctrl +Period to insert the right arrow known as the "symbolic equal sign."
Solve the integral of f(x) symbolically this is g(x)
set x0=2 y0=4
constant of integration C = y(0)-g(x0)
Then F(x) [red]=[/red] g(x)+ C
[red]=[/red] is the symbolic equal arrow pointing to right (Press Ctrl +Period to insert the right arrow known as the "symbolic equal sign."
Here is one way on how to do it
soory here is the correction to the above post
Solve the integral of f(x) symbolically this is g(x)
set x0=2 y0=4
constant of integration C = y0-g(x0)
Then F(x) = g(x)+ C
= is the symbolic equal arrow pointing to right (Press Ctrl +Period to insert the right arrow known as the "symbolic equal sign."
soory here is the correction to the above post
Solve the integral of f(x) symbolically this is g(x)
set x0=2 y0=4
constant of integration C = y0-g(x0)
Then F(x) = g(x)+ C
= is the symbolic equal arrow pointing to right (Press Ctrl +Period to insert the right arrow known as the "symbolic equal sign."
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