Limit #1, Current: The maximum allowable current is determined by heating and is relatively unchanged by frequency changes.
Limit #2, Maximum voltage: The maximum voltage is limited more by by saturation than by insulation, and saturation is directly related to frequency.
Single phase example:
Hence maximum safe KVA = "Amps" times "Test frequency (F1) voltage times (test frequency/frequency of interest (F2)).
Or Maximum KVA = I x E x(F2/F1)
Or
KVA at 50 Hz = 22 Amps x 400 Volts/1000 = 8.8 KVA (50Hz/50Hz) = 1
KVA at 60 Hz = 22 Amps x 480 Volts/1000 = 10.56 KVA (60Hz/50Hz) = 1.2
8.8 KVA x 1.2 = 10.56 KVA
400 Volts x 1.2 = 480 Volts.
I have done similar calculations many times, in both directions for motor horsepower and occasionally for control circuit transformers, when imported 50Hz equipment was being converted for 60 Hz operation.
Impedance voltage by the test definition is the percent of rated voltage required to drive full load current through a short circuit secondary.
The target current is 22 Amps for both frequencies.
For 5%Imp, the voltage required at 50 Hz will be 5% of 400 Volts.
For 5%Imp, the voltage required at 60 Hz will be 5% of 480 Volts.
The only time you need to involve KVA in impedance PU calculations, when the rated full load current is not readily available. In that instance you will use rated KVA and rrated voltage to calculate rated Amperes.
You may need to know the KVA for loading calculations,but you have no further need of KVA for %imp voltage calculations or conversions.
Motor calculations, on the other hand, are generally to determine HP at a different frequency. HP is roughly analogous to KVA, and we are not interested in the %imp values, which in any case, change with motor loading.
The same formula is used, but the formula is transcribed to find a different unknown variable.
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Ohm's law
Not just a good idea;
It's the LAW!