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Hydrostatic Pressure simulation 1

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mustaq

Mechanical
Jun 9, 2014
12
Hello everyone,

I have a bus fuel tank filled with benzene, because of the weight of the fluid there will be pressure acting on the bottom of the surface. So, i am trying to do simulation and the load type selection is Hydrostatic pressure beacuse its a hollow tank filled with liquid. But i have a problem to apply the vector and dailog.

I have already calculted Pressure with Benzene density= 876.5 kg/m^3, Gravitational constant=9.81 m/s^2, height of the tank =560x10^-3 m then the prssure (P=4515.14 N/mm^2)

I have three questions
1)In the Hydrostatic dailog box they have given an option to insert the properties like liquid density, gravitation constant, surface pressure. So, now i have already pressure P= 4815.14 n/m^2 then should i need to mention theses properties again.?
2) The pressure which i calculated should insert in surface pressure box. if not then what is surface pressure..?
2)the vector position is -Z and should be on the bottom of the tank. then where should i specify the point.?
I have attached the model and the daiog box of the hydrostatic pressure.
Kindly, reply.

I will appreciate for your support.
thanking you,

Regards,
Mustaq
Master Thesis student,
Daimler AG, Germany.

 
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The surface pressure is the "air" pressure (or other gas) that is acting on your liquid's free surface. Under standard conditions it is 1 atm (101325 Pa). If the tank is pressurized or you are dealing with something other than standard conditions, you will enter the appropriate value here.

www.nxjournaling.com
 


Thank you Cowaski,

The tank is not pressurized, its just filled with fluid(benzene)
So, I should insert surface pressure(air or gas) 1 atm(101325 Pa), Benzene density= 876.5 kg/m^3, Gravitational constant=9.81 m/s^2 ? the height of the tank should be ignored..??

and what about the direction and the point. will you please tell where should i need to specify these..?

Regards,
Mustaq
Master Thesis student,
Daimler AG, Germany.
 
The vector represents the direction in which gravity is acting, the point defines the location of the surface of the liquid.

www.nxjournaling.com
 
Yes I specified the vector direction on the bottom of the tank (-z direction) and I also specified point on the surface of the tank.

But what I assume in my last messege is correct. I will repeat again
surface presse 1 atm(standard condition, no pressurised condition), Benzene density= 876.5 kg/m^3, Gravitational constant=9.81 m/s^2.

Regards,
Mustaq
Master Thesis student,
Daimler AG, Germany.



 
the height of the tank should be ignored..??

The depth of the fluid is what is important to specify; the height of your tank is defined by the geometry.

It appears that you have only applied the load to the bottom surface of your tank. Are you not interested in the pressure acting on the sides of the tank?

www.nxjournaling.com
 
yes, I am also interested in the pressure which is acting on the sides of the tank.

Ofcourse there is pressure acting on all sides of the tank.
should i need make new simulation for this pressure acting on the side..??

thank you,

Regards,
Mustaq
Master Thesis student,
Daimler AG, Germany.



 
You can make a new simulation if you like, but I don't think it is required. Edit your pressure load and apply it to all the surfaces of the tank that the liquid contacts.

www.nxjournaling.com
 
The tank is fully filled so, the liquid is contact with everywhere side.
The Tank have non uniformed shaped, i mean its not like rectangular or square shape. you can have a look, i have already attached in my first messege. I have attached the image and the model as well.

 
I already looked at the image file. It appeared that the hydrostatic load was only applied to the bottom surface, hence my previous comment.

www.nxjournaling.com
 
so i should select all the faces of the tank to apply pressure load..?
 
I tried but it doesnt work beacuse on the side face there are many other parameters and unable to add pressure load to all the body.
 
Look at the result. I have attached the Image file.. It looks like the bottom surface is goig inside which is not correct.

The liquid is inside and the load is from inside. but the result is reversed.

I hve applied pressure load on the bottom of the tank only.
 
 http://files.engineering.com/getfile.aspx?folder=3e679eaa-8140-4a93-bc15-37892624c029&file=HP.JPG
You'll need to apply the load to the inside surfaces of the tank. The load as currently defined specifies that the tank is submerged in the liquid and the pressure is magically only acting on the bottom surface.

www.nxjournaling.com
 
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