joeNx,
If you want to know about output motor due to changes in frecuencie and voltage you can use this formula:
KW= (N-m x RPM)/9549. where KW: Kilowatt (HP/1.34)- RPM: Speed and N-m : Torque. Assuming you have a 4 Pole Motor, the Synch RPM is 1800. RPM Synch = 120 x F / Poles
In your case the Voltage/Frecuencie Ratio will remain constant and N-m (Torque)too.For it the 60 Hz Torque will be N-m (60 Hz)= 75 x 9549/1800= 397.875
For 50 Hz operation the new RPM will be 1500 then the New KW = 397.875 x 1500/9549 = 62.5. So this confirm why you have to re-rated the motor´s power using a factor of 5/6 (0.833).Some important aspect Due to the speed reduction is the motor´s cooling, at 50 Hz the motor will run slower and the motor´s fan too, so wach up the operating temperature.
Regards
Petronila