Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations cowski on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

How to find the position of the joint axis for Eccentrically Loaded Joints in ECSS-E-HB-32-23A

G_Arbuckle

Mechanical
Joined
Mar 10, 2025
Messages
3
Hi,
I'm currently trying to use ECSS-E-HB-32-23A to analyse an eccentrically loaded joint. Some of the key variables in this analysis depend on dimensions measured from the joint axis O-O (in figure below). However, I can't seem to find anything saying how to determine the position of this axis.
Can someone help me with this? Am I missing something obvious in the handbook or misunderstanding what that axis is for.
1751529203642.png
 
it should be defined in the report, but my guess is the NA of the effective plates (that make up the joint) ... the effective widths of the flanges
 
it should be defined in the report, but my guess is the NA of the effective plates (that make up the joint) ... the effective widths of the flanges
In the standard it says "The joint axis (O-O) is defined to lie at the centroid of the interface pressure distribution." but I'm not sure how to calculate this.
What do you mean by NA?
 
ok, I downloaded the report ... the term "joint axis O-O" is not well defined, there is a lot (TLDR) in chapter 8 about this, maybe this clarifies the meaning. Else, contact the authors.
 
Similar Forum thread, 2013?

Threaded fastener calculations using ECSS-E-HB-32-23A​


BTW... the example [ECSS-E-HB-32-23A, Figure 8-1] makes very little sense to me.
 
Last edited:

Part and Inventory Search

Sponsor

Back
Top